Monday, July 30, 2018

Why are the living organisms classified? I want a short to the point answer

Living organisms are classified because of the following reasons:

(i) Easy identification.

(ii) Study of organisms of other places.

(iii) Study of fossils

(iv) Grouping helps in study of all types of organisms whi9le it is impossible to study individually all of them.

(v) It brings out similarities and disimilarities. They help in knowing relationships among different groups.

(vi) Evolution of various taxa can be known.

What is double circulation?

Double circulation
The type of circulatory system that occurs in mammals, in which the blood passes through the heart twice before completing a full circuit of the body. Blood is pumped from the heart to the lungs and returns to the heart before being distributed to the other organs and tissues of the body. The heart is divided into two separate compartments to prevent oxygenated blood returning from the lungs from mixing with deoxygenated blood from the other parts of the body.
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dimension of pressure is same as a) energy b) force c) energy per unit volume d) force per unit volume

w e space k n o w space t h a t space p r e s u r e equals fraction numerator f o r c e over denominator a r e a end fraction equals fraction numerator M L space T to the power of negative 2 end exponent over denominator L squared end fraction equals M L to the power of negative 1 end exponent T to the power of negative 2 end exponent n o w space c h e c k space y o u r space a n s w e r F i r s t space c h e c k space a n s w e r space left parenthesis b right parenthesis f o r c e F o r c e equals M a s s cross times space a c c e l e r a t i o n space equals M space cross times L cross times T to the power of negative 2 end exponent equals M L space T to the power of negative 2 end exponent c h e c k space o p t i o n space a right parenthesis space e n e r g y e n e r y space equals space f o r c e space cross times space d i s tan c e equals left parenthesis M space cross times L cross times T to the power of negative 2 end exponent right parenthesis cross times L space space space space space space space space space space space space equals M space cross times L squared cross times T to the power of negative 2 end exponent equals M L squared space space T to the power of negative 2 end exponent c h e c k space a n s w e r space left parenthesis C right parenthesis e n e r g y space p e r space u n i t space v o l u m e equals fraction numerator e n e r g y over denominator v o l u m e end fraction equals fraction numerator M L squared space space T to the power of negative 2 end exponent over denominator L cubed end fraction equals M L to the power of negative 1 end exponent T to the power of negative 2 end exponent o p t i o n space C space m a t c h space t h e space p r e s s u r e space d i m m e n s i o n c h e c k space a n s w e r space left parenthesis d right parenthesis f o r c e space p e r space u n i t space v o l u m e equals fraction numerator F o r c e space over denominator v o l u m e end fraction equals fraction numerator M L space T to the power of negative 2 end exponent over denominator L cubed end fraction equals M L to the power of negative 2 end exponent T to the power of negative 2 end exponent o p t i o n space C space i s space c o r r e c t space space space space space space space space space space space space space space

With increased in atomic no.along the period of table from left to right what will be happen with with ionasation energy of element

ionization energy increase from left to right on the periodic table

The ionization energy of the elements within a period generally increases from left to right. This is due to valence shell stability.

Atomic radius decreases from left to right within a period. This is caused by the increase in the number of protons and electrons across a period. One proton has a greater effect than one electron; thus, electrons are pulled towards the nucleus, resulting in a smaller radius. This is caused by electron shielding.

If a, b are the zeroes of f(x) = x2+px+1 and c, d are the zeros of f(x) = x2+qx+1 the value of E = (a−c)(b−c)(a+d)(b+d)

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