A hydroelectric power station takes its water from a lake whose water level is at a height of 50 m above the turbine. Assuming an overall efficiency of 40% , calculate the mass of water which must flow through the turbine each second to produce power output of 1 MW.(g=10 m per s^2).

July 30, 2018 0

since efficiency is 40%
Power = 1 MW =

1 cross times 10 to the power of 6 space W

time = 1 second
h = 50 m
given, g=10
mass = ?
potential energy=P.E = mgh
P.E = mgh= m *10 *50= 500 * m
40 % of potential energy =work = 0.4 * 500 * m = 200* m
power =

fraction numerator w o r k space over denominator t i m e end fraction

=

fraction numerator 200 cross times m over denominator 1 space s e c o n d end fraction

1 cross times 10 to the power of 6 space W

=

fraction numerator 200 cross times m over denominator 1 space s e c o n d end fraction

fraction numerator 1 cross times 10 to the power of 6 over denominator 200 end fraction cross times 1 space s e c o n d equals space m a s s m a s s equals 10 to the power of 6 over 200 equals 5000 space k g

mass of water = 5000 kg

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